Angles subtended by an arc in the same segment of a circle are equal.
Proof:
Let ∠AOB be the angle subtended by an arc at the centre of a circle, O.
The angle subtended by an arc at the centre of a circle is twice the angle subtended at any point on the circumference.
∠ADB=\(\frac{1}{2}\)∠AOB and ∠ACB=\(\frac{1}{2}\)∠AOB
∠ADB =∠ACB = \(\frac{1}{2}\)∠AOB
Hence proved directly from Theorem 2.
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